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3 years ago

Which relation is a function? Please help I need asap

Mathematics

1 answer:

Alisiya [41]3 years ago

3 0

Answer:

Probably A, can't see all of D

Step-by-step explanation:

I can't see the last of D, so I will still try.

A function means that each x only goes to one y, but each y can have multiple xs going to it. If that's hard to understand, on the table, if you have two of the same xs on the x side, they HAVE to have the same y on the y side. Simple as that.

Right away, A looks right since it doesn't repeat anything on the x side, it has 4, 5, 6 and 7. Let's look at the others.

B repeats 3, but the ys are different, one has 10 and one has 30, so this isn't a function. They would both have to be 10 or 30 or some other number.

C repeats -5 and both have a different y, 2 and 3, so not a function

D I can only see the first two x entries so I can't be sure, so maybe you can tell. If there is any repeat int he x side and the corresponding y side isn't the same then it also isn't the function. i have to assume there is a repeat though.

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Answer:

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Step-by-step explanation:

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3 years ago

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Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

3 years ago

Read 2 more answers

Wizer.me<br> What is the leading coefficient of this polynomial?<br> 4x3+8x5-4x2+1x

lakkis [162]

Answer:

8 is the required answer.

Step-by-step explanation:

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3 years ago

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MA_775_DIABLO [31]

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3 years ago