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4 years ago

K-29

Mathematics

1 answer:

Annette [7]4 years ago

3 0

Answer:

0.0125

Step-by-step explanation:

I made the rate equal to one hour, or 1.5/2

0.75 to an hour. then divided 0.75 by 60 to get each minute. giving me 0.0125. I then checked it by multiplying 0.0125 by 120. the proportion of how many minutes in two hours.

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Carlos tiene una produccion semanal de 500kg de papas negras y 600kg de batatas al cabo de 12 semanas de ¿cuanto sera la producc

REY [17]

Step-by-step explanation:

1.Producción semanal de papas negras:500kg x 12 semanas=6.000kg por 12 semanas de papa negra

2.Producción semanal de batatas: 600 kg x 12 semanas=7.200kg por 12 semanas de batata

3.Producción total: Para obtenerla producción total sumamos el total producido por las 12 semanas entre papa negra y batata.Entonces tenemos:

6.000kg de papa negra + 7.200 kg de batata=13.200 kg de producido total entre papa negra y batata por 12 semanas

4 0

3 years ago

Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b

Rina8888 [55]

Answer:

The food preferences among vole species are independent of one another.

Step-by-step explanation:

The hypothesis can be defined as follows:

H₀: The food preferences among vole species are independent of one another.

Hₐ: There is a relationship between voles and food preference.

The data provided is:

meadow voles common voles

apple slices 15 21

peanut butter-oatmeal 25 16

A Chi-square test for the Goodness of fit will be used.

The expected values are computed using the formula:

$E_{i}=\frac{\text{ith Row Total}\times \text{jth Column Total}}{N}$

Consider the Excel sheet attached.

The Chi-square statistic value is 2.861.

Compute the degrees of freedom as follows:

df = (r - 1)(c - 1)

= (2 - 1)(2 - 1)

= 1

Compute the p-value as follows:

$p-value=P(\chi^{2}_{(1)}>2.861)=\text{CHISQ.DIST.RT(2.861,1)}=0.091$

The p-value = 0.091 > α = 0.05

The null hypothesis will not be rejected.

Thus, it can be concluded that the food preferences among vole species are independent of one another.

4 0

3 years ago

We want to evaluate dog owners’ reactions to a new dog food product formulation that contains more vegetables. A promotional boo

Arada [10]

Answer:

Inherently asymmetrical casual relationship.

Step-by-step explanation:

The dog owners are given free dog food samples which contain new vegetables. These samples are given to them by organizing booths at the dog events. The reaction of the dog owners is observed towards this new dog food. This an example of inherently asymmetrical relationship.

6 0

3 years ago

Solve and graph the following inequalities

Lelechka [254]

6x+8 <62
-8 < -8
6x/6 54/6

Answer: x< 9

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3 years ago

What is the value of (fog) (-5)

DochEvi [55]

$f(x)=2x+1,\ g(x)=x^2\\\\(f\circ g)(x)=2(x^2)+1=2x^2+1\\\\(f\circ g)(-5)=2(-5)^2+1=2(25)+1=50+1=51$

6 0

4 years ago