Equations
Let the number of liters of 80% acid = x
Let the number of liters of 40% acid = y
x + y = 2
80%x + 40%y = 65% * 2
Step One
multiply the 2nd given by 100
(80/100)x + (40/100)y = (65/100)*2
80x + 40y = 2*65 = 130 (3)
Step Two
Multiply the first given equation by 80
80x + 80y = 160 (4)
Step Three
Subtract (4) - (3)
80x + 80y = 160
<u>80x + 40y = 130</u>
40y = 30 Divide by 40
y = 30/40
y = 3/4 = 0.75
What you have found is that out of 2 liters, 0.75 L must be the 40% acid.
Step Four
Find the 80% volume
x + y = 2
y = 0.75 L
x + 0.75 = 2
x = 2 - 0.75
x = 1.25 L
Answers
80% Volume = 1.25 L
40% Volume = 0.75 L
Answer:
2x² + 7x - 4
Step-by-step explanation:
(2x-1)(x+4)
= (2x)(x) + (2x)(4) + (-1)(x) + (-1)(4)
=2x² + 8x - x -4
=2x² + 7x - 4
The answer would be 8 tenths because the digit is 8 and it's in the tenths place.
Answer:100,000
Step-by-step explanation:
