Which Expressions are equivalent to the following 30x2-5x-10

A 15 m pole is leaning against a wall. The foot of the pole is 10 m from the wall. Find the angle the pole makes with the ground

nataly862011 [7]

Answer:

∅ ≈ 48.2º

Step-by-step explanation:

cos∅ = adj/hyp = 10/15 = 2/3

Therefor

∅ = arccos 2/3

use calculator

∅ = 48.189685104221402

∅ ≈ 48.2º

5 0

3 years ago

1. Jason travelled from Florida to Mississauga He travelled 3/10 of the journey by lorry, 2/5 of the journey by taxi and the res

sukhopar [10]

Answer:

1. He traveled 3/ 10 by train

2. 3/4 is the greatest

Step-by-step explanation:

3/ 10 = Iorry

2/5 = taxi

? = train

2=4

5=10

4+ 3 = 7

10 + 10= 10

13/20

12/20

15/20

17/20

5 0

3 years ago

20 POINTS How do you find the interquartile range

kari74 [83]

Answer:

To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Step-by-step explanation:

(Khan Academy)

3 0

2 years ago

Read 2 more answers

The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

Let $\mu$ = average sodium content.

So, Null Hypothesis, $H_0$ : $\mu$ = 1100 milligrams {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 1100 milligrams {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample average sodium content = 1088.64 milligrams

s = sample standard deviation = 234.12 milligrams

n = sample of packages of Oriental Spice Sauce = 40

So, test statistics = $\frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}$ ~ $t_3_9$

= -0.307

The value of z test statistics is -0.307.

Since, in the question we are not given the level of significance so we assume it to be 5%. Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0

3 years ago

Marcus ate half of a pizza on Monday night. He then ate one third of the remaining pizza on Tuesday. Which of the following expr

Strike441 [17]

Option E

The expression show how much pizza Marcus ate in total is:

$Total = \frac{1}{2} + \frac{1}{3} \times \frac{1}{2}$

Solution:

Given that,

Marcus ate half of a pizza on Monday night

He then ate one third of the remaining pizza on Tuesday

Therefore,

$Monday\ night = \frac{1}{2}\\$

Remaining is given as:

$Remaining = 1 - \frac{1}{2} = \frac{1}{2}$

He then ate one third of the remaining pizza on Tuesday

Therefore,

$Tuesday = \frac{1}{3} \times \frac{1}{2}$

Thus expressions show how much pizza Marcus ate in total is:

Total = monday night + tuesday

$Total = \frac{1}{2} + \frac{1}{3} \times \frac{1}{2}$

Thus Option E is correct

3 0

3 years ago