[(17-9) x (3x2)] / 2

When finding the intersection of two lines from both Algebra I and Geometry, you first "set the linear equations equal" to each

Step2247 [10]

Answer:

hola quetall cm eatanfufuguvuggugdyfyxjcjv

5 0

2 years ago

I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the

Ugo [173]

Assuming the equation is:

$\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)$

When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.

Here the denominators are 2 and 10, hence the LCM is 10.

Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

$10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)$

simplify, remember that there are always implied parentheses around numerators and denominators:

$5x-(10x-25)=30(x+3)-10(x-14)$

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5

In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

$\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)$

simplify, remember that there are always implied parentheses around numerators and denominators:

$2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)$

$x-(2x-5)=6(x+3)-2(x-14)$

Now, distribute, i.e. remove parentheses and distribute:

$x-2x+5=6x+18-2x+28$

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

7 0

3 years ago

Read 2 more answers

Is sin(x) even or odd ? prove with examples ?

zloy xaker [14]

Answer:

$\text{sin}(x)$ is an odd function.

Step-by-step explanation:

We are asked to prove whether $\text{sin}(x)$ is even or odd.

We know that a function $f(x)$ is even if $f(x)=f(-x)$ and a function $f(x)$ is odd, when $f(-x)=-f(x)$ .

We also know that an even function is symmetric with respect to y-axis and an odd function is symmetric about the origin.

Upon looking at our attachment, we can see that $\text{sin}(x)$ is symmetric with respect to origin, therefore, $\text{sin}(x)$ is an odd function.

4 0

3 years ago

Read 2 more answers

Neeeeeed heeelp plz!!!

Blababa [14]

|
|__x_- 4___________ 2x³/2x² =x
2x² + 2x +3 | 2x³ - 6x² +7x +3
- (2x³ +2x² +3x)
 -8x² +4x +3 -8x²/2x² = -4
-(-8x² -8x -12)
 12x +15

(x-4) + (12x +15)/(2x² + 2x +3)

6 0

3 years ago

Solve the equation.

lawyer [7]

Answer:

x=12
x=9

Step-by-step explanation:

1) Eliminate parentheses:

0.1x +18.8 = -4 +2x

22.8 = 1.9x . . . . . . . . . add 4 - 0.1x

12 = x . . . . . . . . . . . . . divide by 1.9

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2) Eliminate parentheses:

-16 +4x = 0.8x +12.8

3.2x = 28.8 . . . . . . . . add 16 - 0.8x

x = 9 . . . . . . . . . . . . . .divide by 3.2

_____

Comments on the solutions

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

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You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.

7 0

3 years ago