All categories

3 years ago

Evaluate 1/2a^-4b^2 for a=-2 and b=4 A) 2 B) 1/2 C)3 D)4

Mathematics

1 answer:

shepuryov [24]3 years ago

5 0

Answer:

The answer to your question is: letter B) 1/2

Step-by-step explanation:

Data

a = -2

b = 4

Equation

(1/2)a⁻⁴b²

Substitution

= (1/2)(-2)⁻⁴(4)²

= (1/2) (1 /2⁴)(4)²

= 1/2 (1/16) (16)

= 16 / 32

= 1 / 2

You might be interested in

The probability of winning a game is 40%. You play 60 times. How many times do you expect win? PLZZZZZ HELP MEEE!!!!

Molodets [167]

You espect wint the 40% of 60:
40% of 60=(40/100)*60=(40*60)/100=24

Answer: you expect win 24 times.

4 0

3 years ago

Read 2 more answers

What is the value of x Triangle with sides 10 6 x-6

Grace [21]

Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14

5 0

3 years ago

Xanthe and Sarah do some fundraising for their local nursing home. Together they raised $$$302. If Xanthe raised $$$102 more tha

Dimas [21]

Given :

Xanthe and Sarah together raised $302 .

If Xanthe raised $102 more than Sarah .

To Find :

The amount raised by Sarah .

Solution :

Let , amount raise by Sarah is x .

So , by the relation given , price raised by Xanthe is 102 + x .

Now , sum of their amount raised is :

$x+(x+102)=302\\\\2x=302-102\\\\x=\$100$

Therefore , the amount raised by Sarah is $100 .

Hence , this is the required solution .

6 0

3 years ago

Helpppppppppppppppppppppp..... .......

morpeh [17]

Answer:

${ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}$

3 0

2 years ago

Please answer this I am to lazy to think right now

notka56 [123]

QUESTION:- WHICH FRACTION IS THE RECIPROCAL OF $\frac{4}{3}$

$RECIPROCAL = \frac{3}{4}$

8 0

2 years ago