How do i solve 2tan^2xsinx-tan^2x=0

1 answer:

8 0

2tan²xsinx - tan²x = 0
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Transpose tan²x to the right side of the equation
2tan²xsinx = tan²x
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Divide the whole equation with tan²x
tan²x will be cancelled out
tan²x ÷ tan²x = 1
2sinx = 1
sinx = 1/2
x = arcsin(1/2)
x = 30degrees or π/6

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poizon [28]

Answer:

(86.2,0) is the x-intercept.

Step-by-step explanation:

You can use the slope formula to figure this one out:

Just use two of the points on the table, any of them will work:

$(33,-22)\\(52,-33)$

$\frac{-22-33}{33-52} =\frac{-55}{-19}=\frac{55}{19}$

Now you have the slope of the equation, now using the y-intercept equation you can substitute the variables for point of the table and the new slope.:

$(71,-44)\\y=mx+b\\-44=\frac{55}{19} (71)+b$

Now just solve for b to get the y intercept:

$-44=\frac{55}{19}(71)+b\\-44= \frac{3905}{19} +b\\(-\frac{3905}{19})-44=\frac{3905}{19} +b(-\frac{3905}{19})\\ -\frac{4741}{19}=b$

Now you have the y-intercept so you just have to plug in 0 to the y spot and it will calculate the x-intercept.

$0=\frac{55}{19}x-\frac{4741}{19}\\(+\frac{4741}{19})0=\frac{55}{19}x-\frac{4741}{19}(+\frac{4741}{19})\\\\\frac{4741}{19}=\frac{55}{19}x\\\frac{\frac{4741}{19}}{\frac{55}{19} }= \frac{\frac{55}{19} x}{\frac{55}{19} } \\\frac{431}{5} =x\\or\\86.2=x$