Answer:
1 and 4 has same pairs of solution.
Step-by-step explanation:
Solutions for the given equations are:
\begin{gathered}1. (x+6)(x - 6) = 0\\(x+6) = 0, (x-6) = 0\\x = -6, x = 6\\\\2. (x + 6)(x + 6) = 0\\(x+6) = 0, (x+6) = 0\\x = -6, x = -6\\\\3. (x - 6)(x - 6) = 0\\(x-6) = 0, (x-6) = 0\\x = 6, x = 6\\\\4. (2x + 12)(2x - 12) = 0\\(2x+12) = 0, (2x-12) = 0\\x = -6, x = 6\\\\5. (2x - 12)(x - 12) = 0\\(2x-12) = 0, (x-12) = 0\\x = 6, x = 12\\\\6. (x+12)(x - 12) = 0\\(x+12) = 0, (x-12) = 0\\x = -12, x = 12\\\\7. (x +12)(x-6) = 0\\(x+12) = 0, (x-6) = 0\\x = -12, x = 6\end{gathered}
1.(x+6)(x−6)=0
(x+6)=0,(x−6)=0
x=−6,x=6
2.(x+6)(x+6)=0
(x+6)=0,(x+6)=0
x=−6,x=−6
3.(x−6)(x−6)=0
(x−6)=0,(x−6)=0
x=6,x=6
4.(2x+12)(2x−12)=0
(2x+12)=0,(2x−12)=0
x=−6,x=6
5.(2x−12)(x−12)=0
(2x−12)=0,(x−12)=0
x=6,x=12
6.(x+12)(x−12)=0
(x+12)=0,(x−12)=0
x=−12,x=12
7.(x+12)(x−6)=0
(x+12)=0,(x−6)=0
x=−12,x=6
(x+6)(x - 6) = 0 and (2x + 12)(2x - 12) = 0 have same pair of solutions.
Step-by-step explanation:
there you go :)
Answer:
30.2 - 13.7=n
Step-by-step explanation:
To get how far he ran you have to subtract 30.2 from 13.7 therefore giving you 16.5 which will be the total distance he ran after lunch.
Answer:
Step-by-step explanation:
t2/t1=r
-10/2=-5
2*-5=-10
Answer:
<em>In 5 years the product of their ages will be 208</em>
Step-by-step explanation:
The age of two children is 11 and 8 years.
Let's call x the number of years ahead.
We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:
(11+x)(8+x)=208
Operating:
Simplifying:
Factoring:
(x-5)(x+24)=0
Solving:
x=5, x=-24
The negative solution is not valid, thus x=5
In 5 years the product of their ages will be 208
Answer:
C. Median
Step-by-step explanation:
If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.
