Answer:
mole fraction benzene = 0.62
mole fraction toluene = 0.38
Explanation:
Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:
<h2>p total = x₁ P⁰₁ + x₂ P⁰₂</h2>
where x1 and x2 for this solution denote the mole fractions of benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.
Solving the algebraic equation:
75 x₁ + 22 x₂ = 55
75 x₁ + 22 ( 1- x₁) = 55 (since x₁ + x₂ = 1)
75 x₁ + 22 - 22 x₁ = 55
53 x₁ = 33
x₁ = 0.62
x₂ = 1 - 0.62 = 0.38
<u>Answer:</u> The volume of NaOH solution required to reach the half-equivalence point is 0.09 mL
<u>Explanation:</u>
The chemical equation for the dissociation of butanoic acid follows:
The expression of 
for above equation follows:
![K_a=\frac{[CH_3CH_2CH_2COO^-][H^+]}{[CH_3CH_2CH_2COOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BCH_3CH_2CH_2COO%5E-%5D%5BH%5E%2B%5D%7D%7B%5BCH_3CH_2CH_2COOH%5D%7D)
We are given:
![[CH_3CH_2CH_2COOH]=0.888M\\K_a=1.54\times 10^{-5}](https://tex.z-dn.net/?f=%5BCH_3CH_2CH_2COOH%5D%3D0.888M%5C%5CK_a%3D1.54%5Ctimes%2010%5E%7B-5%7D)
![[CH_3CH_2CH_2COO^-]=[H^+]](https://tex.z-dn.net/?f=%5BCH_3CH_2CH_2COO%5E-%5D%3D%5BH%5E%2B%5D)
Putting values in above expression, we get:
![1.54\times 10^{-5}=\frac{[H^+]^2}{0.888}](https://tex.z-dn.net/?f=1.54%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%5BH%5E%2B%5D%5E2%7D%7B0.888%7D)
![[H^+]=-0.0037,0.0037](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D-0.0037%2C0.0037)
Neglecting the negative value because concentration cannot be negative
To calculate the volume of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is butanoic acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of NaOH solution required to reach the half-equivalence point is 0.09 mL
Answer:
Mass is the measure of how much matter is in an object
Explanation:
˙˚ʚ(´◡`)ɞ˚˙
Explanation:
a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.
b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.
c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.
d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.
