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Soloha48 [4]
3 years ago
9

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are Cu2+(aq)+2e−→Cu(s) and Fe(s)→Fe2+(aq)+2e− The net reaction is Cu2+(aq)+Fe(s)→Cu(s)+Fe2+(aq) Use the given standard reduction potentials in your calculation as appropriate.
Chemistry
1 answer:
inessss [21]3 years ago
3 0

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)

Reduction at cathode :

Cu^+(aq)+2e^-\rightarrow Cu(s)

Reduction potential of  Cu^{2+} to Cu=E^o_{1}=0.34 V

Oxidation at anode:

Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction potential of  Fe^{2+} to Fe=E^o_{2}=-0.44 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=0.34V -(-0.44 V)=0.78 V

The standard cell potential of the reaction is 0.78 Volts.

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Zn-64 = 48.63%
Ann [662]

Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u

So, the average atomic mass of zinc is 65.46 u.

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3 years ago
:Why is a fuse used as a<br> safety feature in a circuit
julia-pushkina [17]

Explanation:

The fuse breaks the circuit if a fault in an appliance causes too much current to flow. This protects the wiring and the appliance if something goes wrong. The fuse contains a piece of wire that melts easily.

4 0
3 years ago
1.Which has a larger radius Ca atom or Ca+2 ion?
arsen [322]

Answer:

1.Ca atom has greater radius than Ca+2

2.F- ion has larger radius than F

4 0
3 years ago
Genetic Information DNA is coiled into chromosomes in a cell’s .
puteri [66]
Nucleus is the right answer i guess
7 0
3 years ago
Chlorine has two natural isotopes, chlorine-35 and chlorine-37.
Alex Ar [27]

Answer:

The relative atomic mass of chlorine depends on the ratio between the abundance of these two naturally-occurring isotopes.

Explanation:

The relative atomic mass of an element is a weighted average of the atomic mass of its naturally-occurring isotopes. The relative abundance of each isotope gives its weight in this weighted average.

For these two naturally-occurring isotopes of chlorine:

  • The relative atomic mass of ^{35}{\rm Cl} is approximately 34.969 daltons. The relative abundance of this isotope in nature is approximately 0.758.
  • The relative atomic mass ^{37}{\rm Cl} is approximately 36.966 daltons. The relative abundance of this isotope in nature is approximately 0.242.

\begin{array}{|c|c|c|}\cline{1-3} \text{Isotope} & \text{Atomic Mass} & \text{Relative Abundance}\\ \cline{1-3} ^{35}{\rm Cl} & \approx 34.968\; \rm Da} & \approx 0.758 \\ \cline{1-3} ^{37}{\rm Cl} & \approx 36.966\; \rm Da & \approx 0.242 \\ \cline{1-3}\end{array}.

\begin{aligned}&\text{relative atomic mass of Cl} \\ &= \text{atomic mass of $^{35}{\rm Cl}$} \times \text{relative abundance of $^{35}{\rm Cl}$} \\&\quad + \text{atomic mass of $^{37}{\rm Cl}$} \times \text{relative abundance of $^{37}{\rm Cl}$} \\ &\approx 34.968\; \rm Da \times 0.758 + 36.966\; \rm Da \times 0.242 \\ &\approx 35.45\; \rm Da \end{aligned}.

The relative abundance of ^{35}{\rm Cl} is much higher than that of ^{37}{\rm Cl}. Consequently, the relative atomic mass of the element \rm Cl is closer to the atomic mass of ^{35}{\rm Cl}\! than that of ^{37}{\rm Cl}\!.

7 0
3 years ago
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