Answer:
1.75M
Explanation:
The problem deals with finding the molarity of the given compound.
The compound is:
Na₂SO₄.10H₂O
Mass of the compound = 10.5kg = 10500g
Volume of the compound = 18.6L
Molarity is the number of moles of solute in a solution;
Molarity =
Number of moles =
Molar mass of Na₂SO₄.10H₂O = 2(23) + 32 + 4(16) + 10[2(1) + 16]
= 322g/mol
Now;
Number of moles =
= 32.6mole
So;
Molarity =
= 1.75M
Answer:
6.022 x 10²³
Explanation:
Data Given:
mass of carbon = 12.01 g
individual particles = 6.02 x 10²³
number of atoms = ?
Solution:
Formula used to find the number of atoms
no. of moles = number of atoms / 6.022 x 10²³ . . . . . (1)
So, first we have to find number of moles
Formula to find no. of moles
no. of moles = mass in grams/ molar mass. . . . . (2)
molar mass of Carbon = 12.01 g/mol
Put values in eq.2
no. of moles = 12.01 g / 12.01 g/mol
no. of moles = 1 mol
Now put the values in eq. 1
no. of moles = number of atoms / 6.022 x 10²³ . . . . . (1)
1 mol = number of atoms / 6.022 x 10²³
Rearrange the above equation
number of atoms = 1 mol x 6.022 x 10²³
number of atoms = 6.022 x 10²³
So it is 6.022 x 10²³ atoms in 12.01 grams of carbon. This 6.022 x 10²³ also Known as Avogadro's number that is one mole of any substance consists this number of atoms.
The number of molecules of water is calculated as follows
find the moles of water= moles=mass/molar mass
moles = 69.1g/18 g/mol = 3.84 moles
by use of Avogadro law constant
that is 1 mole = 6.02 x10^23 molecules what about 3.84 moles of water
the molecules of water = (3.84 x 6.02 x10^23) = 2.312 x10^24 molecules
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