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Genrish500 [490]
3 years ago
7

Write an equation given the following: m = -1, y-int = 8 *

Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer: y = -1x+8

Step-by-step explanation:

y=mx+b

M is your slope

B is your y-int

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Esperanza buys a new toy for $10.50 plus 4% tax. Then she buys new shoes for $28 plus 6% tax. Enter the sum that Esperanza paid,
Nataliya [291]

Answer:

$40.60

Step-by-step explanation:

10.50+4%=10.92

28+6%=29.68

10.92+29.68=40.60

4 0
2 years ago
Which does not show a direct variation between x and y?
Zepler [3.9K]
A direct variation is a mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other. In other words, a direct variation is where y = x * (constant).

In answer a, y = x*.5, so it is a direct variation.
In answer c, y = x* \frac{1}{9}, so it is a direct variation.
In answer d, y = x*2, so it is a direct variation,

Only answer b is left, which means the answer must be 'b'. 

We also know 'b' is the answer because it cannot be expressed as <span>y = x * (constant). Instead, it is expressed as </span>y =  \frac{constant}{x}, which is not the same thing and is therefore not a direct variation.

Hope I helped, and let me know if you have any questions :)
8 0
3 years ago
Read 2 more answers
2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books
insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

  • When the books are arranged in any order, the number of arrangements is 3628800
  • When the mathematics book must not be together, the number of arrangements is 2903040
  • When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
  • When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

\mathbf{Novels = 3}

\mathbf{Mathematics = 2}

\mathbf{Chemistry = 5}

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

\mathbf{n = Novels + Mathematics + Chemistry}

\mathbf{n = 3 + 2 +  5}

\mathbf{n = 10}

The number of arrangement is n!:

So, we have:

\mathbf{n! = 10!}

\mathbf{n! = 3628800}

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

\mathbf{Maths\ together = 2 \times 9!}

Using the complement rule, we have:

\mathbf{Maths\ not\ together = Total - Maths\ together}

This gives

\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}

\mathbf{Maths\ not\ together = 2903040}

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the novels in:

\mathbf{Novels = 3!\ ways}

Next, arrange the chemistry books in:

\mathbf{Chemistry = 5!\ ways}

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

\mathbf{n =Mathematics + 1 + 1}

\mathbf{n =2 + 1 + 1}

\mathbf{n =4}

So, the number of arrangements is:

\mathbf{Arrangements = n! \times 3! \times 5!}

\mathbf{Arrangements = 4! \times 3! \times 5!}

\mathbf{Arrangements = 17280}

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

\mathbf{Mathematics = 2}

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the mathematics in:

\mathbf{Mathematics = 2!}

Literally, the number of chemistry and mathematics now is:

\mathbf{n =Chemistry + 1}

\mathbf{n =5 + 1}

\mathbf{n =6}

So, the number of arrangements of these books is:

\mathbf{Arrangements = n! \times 2!}

\mathbf{Arrangements = 6! \times 2!}

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

\mathbf{Arrangements = ^7P_3}

So, the total arrangement is:

\mathbf{Total = 6! \times 2!\times ^7P_3}

\mathbf{Total = 6! \times 2!\times 210}

\mathbf{Total = 302400}

Read more about permutations at:

brainly.com/question/1216161

8 0
2 years ago
What is the answer to this ?
erma4kov [3.2K]

Answer:

B shows a translation of three units to the right

8 0
3 years ago
Why are me and mrs numbers so happy
mestny [16]
Because life is great
8 0
3 years ago
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