Answer:
Let the interbred alleles be represente dy the letters A and B for two genes. Gene A will exist in two alleles, that will icnlude A and g while Gene B exists in two alleles, B and r.
The uppercase alleles are dominant to the lowercase alleles. The interbred long-shaped squash is AABB (aabb) and the true-breeding disk-shaped is ggrr AABB.The F1 offspring are AaBb.
The outcome of interbred of the F1 plants and genotypes and phenotype sof F2 for:
1) the disk-shaped phenotype, an offspring must inherit at least one dominant allele from both genes.
1 ggrr+ 2 Agrr+ 2 ggrB+ 4 AgBr = 9 disk-shaped offspring
2) To get the round phenotype, an offspring must inherit at least one dominant allele for one of the two genes but must be homozygous recessive for only one of the two genes.
1 ggrr+ 1 ggBB+ 2 AArB+ 2 gABB = 6 round-shaped offspring
3) To get the long phenotype, an offspring must inherit all recessive alleles:
1 AABB= 1 long-shaped offspring
Hence, the phenotype and genotype of F2 is is 9 disk-shaped offspring and 1 ggrr+ 2 Agrr+ 2 ggrB+ 4 AgBr; 6 round-shaped offspring and 1 ggrr+ 1 ggBB+ 2 AArB+ 2 gABB; and 1 long-shaped offspring and 1 ggrr+ 1 ggBB+ 2 AArB+ 2 gABB respectively.
Inferences cant be the answer because inference is the reason of why the observation happens
It is unchanged and can be used again for the same chemical reaction.
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