<u>Answer:
</u>
The probability of rolling a number greater than 4 or less than 3 is 
<u>Solution:
</u>
In the given question there are two events as follows:
(a) Rolling a number greater than 4 i.e. A = {5,6}
(b) Rolling a number less than 3 i.e. B = {1,2}
Since a die has 6 numbers,
P(A) = 
where P(A) is the probability of occurrence of event A and P(B) =
Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.
P(A∪B) = P(A) + P(B)
Therefore the probability of getting a number greater than 4 or less than 3 is
Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
Answer:
1 2/14 ; 1 1/7
Step-by-step explanation:
To solve, change the division sign to a multiplication sign and flip the second fraction.
(4/7)/(2/4) = (4/7)(4/2)
Multiply across
(4 * 4)/(7 * 2) = (16)/(14)
Simplify. Change to mixed fraction (& further simplify if needed).
16/14 = 1 2/14
~
1/3 because only 1 and 2 is less than 3 out of the 6 numbers. 2/6 = 1/3.
