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butalik [34]
3 years ago
15

Use the graph of the function to estimate the intervals on which the function is increasing or decreasing. (Enter your answers u

sing interval notation.)

Mathematics
1 answer:
Crank3 years ago
3 0

The intervals on which the graph is increasing:   ]-∞,-3[ U ]0.5,-∞[ . On the other hand, the graph is decreasing:  ]-3,0.5[

<h3>Function</h3>

A function can be classified as increasing or decreasing. Thus, a function is increasing when the y-values increase, on the other hand, a function is decreasing when the y-values decrease.

From the image, you can see that the y-values increase in the following x-intervals: from -∞ to -3 and from 0.5 to ∞. Using interval notation, you can write that the function is increasing in:

                                  ]-∞,-3[ U ]0.5,-∞[

From the graph, you can see that the y-values decrease in the following x-intervals: from -3 to 0.5. Using interval notation, you can write that the function is decreasing in:

                                         ]-3,0.5[

Learn more about function here:

brainly.com/question/2649645

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Answer:

Ruby’s function notation V(h) describes the volume of the pool after h number of hours. Hours is the independent variable and the total volume is the dependent variable.

Step-by-step explanation:

sample response

3 0
3 years ago
Read 2 more answers
I need help please! I will mark you as a brainlest and give out 30 points!
klio [65]
Answer:
1entire group
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4random and large enough
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Step-by-step explanation:
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3 0
2 years ago
What is a1? what is d? what’s the equation? what is a7? what is a59?
Zina [86]
Answer:

a1 = 2

d = 3

an = 2 + (n - 1) * 3

a7 = 20

a59 = 176

Steps:

a1 is the initial value (when n equals 1), and since there are 2 crosses, it is 2.

d is the added value to each amount of crosses. And since the second amount is 5 and the third amount is 8, we can determine that each n is adding 3 crosses, therefore making d = 3.

The equation is simply plugging in the values for a1 and d.

A7 is simply plugging in 7 for n in the equation and solving for it. So;

a7 = 2 + (7 - 1) * 3

a7 = 2 + 6 * 3

a7 = 2 + 18

a7 = 20

And same thing as the last for 59 except substitute 59 in for where you put 7;

a59 = 2 + (59 - 1) * 3

a59 = 2 + 58 * 3

a59 = 2 + 174

a59 = 176
8 0
3 years ago
Read 2 more answers
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
A right triangle with vertices J(4, 0), K(0,0), and L(0,5) is rotated around the x-axis. To the nearest tenth of a unit, what is
statuscvo [17]
This is the concept of graphs and volume of the solid figures, given that the triangle J,K,L was rotated along the x-axis, the resultant figure was cone with with radius of 5 units and a height of 4 units;
The volume of a cone is given by;
V=πr^2(h/3)
r=5 units
h=4 units
V=π*5^2*(4/3)
V=104.72 units^3
the answer is B]
5 0
3 years ago
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