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galben [10]
4 years ago
9

Which statement is true about the polynomial 5s6t2 + 6st9 – 8s6t2 – 6t7 after it has been fully simplified?

Mathematics
1 answer:
n200080 [17]4 years ago
6 0

Choices:

It has 3 terms and a degree of 9.

It has 3 terms and a degree of 10.

It has 4 terms and a degree of 9.

It has 4 terms and a degree of 10.

Answer : It has 3 terms and a degree of 10.

5s^6t^2 + 6st^9 - 8s^6t^2 - 6t^7

Simplify the expression

5s^6t^2  - 8s^6t^2 + 6st^9 - 6t^7

Combine like terms

- 3s^6t^2 + 6st^9 - 6t^7

To find degree we add the exponents 's' and 't' of each term

- 3s^6t^2 -->  degree = 8

6st^9 -->  degree = 10 ( 's' has exponent 1)

- 6t^7 -->  degree = 7

Simplified expression is - 3s^6t^2 + 6st^9 - 6t^7

Highest degree is 10

It has 3 terms and a degree of 10


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Dafna11 [192]

Answer:

assuming you want to get rid of the radical here so, 25/2

Step-by-step explanation:

raise the whole fraction to the second power, and the radical will cancel out, then solve 5^2 which is 25. end up with 25 over 2

8 0
3 years ago
What is the length of the hypotenuse? ​
Lady_Fox [76]

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i think its 12

Step-by-step explanation:

7 0
3 years ago
Actor the expression 16x+8x+1 16x 28x +11-​
Gwar [14]
<h3>Explanation:</h3>

\large \purple {\sf { {16x}^{2}  + 8x + 1}}

\large \pink {\sf { =  {(4x)}^{2}  + 2(4x)(1) +  {(1)}^{2}}}

\large \orange {\sf { = {(4x + 1)}^{2} }}

<h2>Answer:</h2>

\large \green {\sf {{16x}^{2}  + 8x + 1 =  {(4x + 1)}^{2}}}

6 0
3 years ago
Please answer i need it in 5-10 minutes please
matrenka [14]

Answer:

it is 5

Step-by-step explanation:

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3 0
3 years ago
Which equation represents a line that is perpendicular to the line passing through (-4,7) and (1,3)?
diamong [38]

The equation perpendicular to the line passing through the points (-4,7) and (1,3) isy=\frac{5}{4}x-2

<h3>Equation perpendicular to a line</h3>

The slope of the given line is calculated as:

m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{3-7}{1-(-4)} \\\\m=\frac{-4}{5}

The equation perpendicular to the given line will be of the form

y-y_1=\frac{-1}{m} (x-x_1)

Substitute x_1=-4, y_1=7, and m=\frac{-4}{5}

y-7=\frac{5}{4}(x+4)\\\\ y=\frac{5}{4}x+5-7\\\\ y=\frac{5}{4}x-2

Therefore, the equation perpendicular to the line passing through the points (-4,7) and (1,3) is y=\frac{5}{4}x-2

Learn more on perpendicular equations here: brainly.com/question/1441594

#SPJ1

6 0
2 years ago
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