Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
int r=26,x,y;//defining integer variable
char c;//defining a character variable
for(x= 1; y<= r; x++)//using for loop for count value
{
for(y= 1; y<= x; y++)//using for loop to convert value in triangle
{
c=(char)(y+64);//convert value into character
cout << c;//print character value
}
cout << "\n";//use print method for line break
}
return 0;
}
Output:
Please find the attachment file.
Explanation:
In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop, in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.
<h2>Answer:</h2>
<u>The correct option is</u><u> (B) hang up and call back using the banks official phone number</u>
<h2>Explanation:</h2>
There are a lot of cases where people pretend to call from the banks where the receivers have the account. The caller tries to take the information from the receiver and pretends to be the bank official. If there is any doubt then the receiver should hang up the call and call back the official number of the bank to confirm that whether somebody has called from the bank to get the information.
One of the things that are a challenge, is that you have to get the correct puntuation, correct capitilization, because it's a buisness email. You ont want to mess a buisness email up. You also have to have no repating phrases and sentences. You can't be adding random words and saying "and" all the time.
Answer:
import java.util.Scanner;
public class ss11{
public static void main (String[]args) {
Scanner keyboard = new Scanner (System.in)
String a1, a2, a3, a4, a5;
int i1, i2, i3, i4, i5;
System.out.println("Enter a four bit binary number:");
a1= keyboard.next();
a2= a1.substring(0,1);
a3= a1.substring(1,2);
a4= a1.substring(2,3);
a5= a1.substring(3,4);
i1 = Integer.parseInt(a2);
i2 = Integer.parseInt(a3);
i3 = Integer.parseInt(a4);
i4 = Integer.parseInt(a5);
i1= i1 * 8;
i2= i1 * 4;
i3= i1 * 2;
i4= i1 * 1;
i5= i1+i2+i3+i4;
System.out.println("The converted decimal number is: +i5);
}
}
Explanation:
