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daser333 [38]
3 years ago
9

scores on the act college entrance exam follow a bell-shaped distribution with mean 18 and standard deviation 6. Wayne's standar

dized score on the ACT was -0.5. what was Wayne's actual ACT score?
Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

His actual score is 15

Step-by-step explanation:

Here, we are interested in calculating Wayne’s actual score on the ACT

when we say the scores have being standardized, it means the score was reported in terms of the z-score and not the initial raw scores.

Now, mathematically, for the scores to have a negative z-score, it means it is actually below the mean.

The formula for the z-score or standard score is given below;

z-score = (x - mean)/SD

where in this case, x = ? which is the score we are looking for , z-score = -0.5 , mean score = 18 and standard deviation of the scores = 6

So, substituting these values into the z-score equation, we have;

-0.5 = (x-18)/6

x-18 = 6(-0.5)

x -18 = -3

x = -3 + 18

x = 15

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Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

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Then:

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The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

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The minus sign is because te pebble is falling down.

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The average velocity is:

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iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

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b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

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Then the velocity at t = 4s is:

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3 years ago
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