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ANEK [815]
3 years ago
12

I really really need help on this... ASAP, i will give a crown to whoever answers it first

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0
C is 23 because if you get all rhe numbers and measure thats your answer. I think i might be wrong. if I am then sorry
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What would the world be like without math or money? why
Phantasy [73]
Everyone would be confused because they wouldnt know how to add. if there wasnt money then there with be no objects/food/toys/ect. unless its all free. If it all free then everyone would go crazy because they wouldnt have to calculate how much the item cost.
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3 years ago
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A cylinder has a radius of 4 inches and a high of 10.5 inches what is the approximate volume of the cylinder
olga55 [171]

Answer:

V ≈ 527.79

Step-by-step explanation:

Formula is V= πr2h

therefore

V = π * 4 * 2 * 10.5

V = π * 8 * 10.5

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5 0
3 years ago
Which represents the inverse of the function f(x) = 4x? h(x) = x + 4 h(x) = x – 4 h(x) = three-quartersx h(x) = one-quarterx
aalyn [17]

Answer:

\large\boxed{f^{-1}(x)=h(x)=\dfrac{1}{4}x}

Step-by-step explanation:

f(x)=4x\to y=4x\\\\\text{exchange}\ x\ \text{to}\ y\to x=4y\\\\\text{solve for}\ y:\\\\4y=x\qquad\text{divide both sides by 4}\\\\\dfrac{4y}{4}=\dfrac{x}{4}\\\\y=\dfrac{1}{4}x

8 0
3 years ago
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Which polynomial represents the algebra tile configuration shown?
Aleks04 [339]

Answer: the answer is D

Step-by-step explanation:

3 0
3 years ago
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Identify the segment bisector of MN Then find MN.<br> ????????? Helppp pleaseee
enot [183]

Given:

The figure.

To find:

The segment bisector of MN and value of MN.

Solution:

From the given figure it is clear that ray RP,i.e., \overrightarrow {RP} is the segment bisector of MN because it divides segment MN in two equal parts.

Now,

3\dfrac{5}{6}=\dfrac{3\times 6+5}{6}

3\dfrac{5}{6}=\dfrac{23}{6}

Since, \overrightarrow {RP} is the segment bisector of MN, therefore,

MN=2\times \dfrac{23}{6}

MN=\dfrac{23}{3}

MN=7\dfrac{2}{3}

Therefore, the length of MN is 7\dfrac{2}{3}.

6 0
3 years ago
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