Short answer: C
Let's start with the pen.
The length is x
The width is 3 more.= x + 3
Perimeter of the pen = 2L + 2W
P = 2 L + 2W
P = 2*x + 2(x + 3)
P = 2x + 2x + 6
P = 4x + 6. Leave that for now.
Area of the pen without the doghouse = x(x + 3)
Area of the pen without the doghouse = x^2 + 3x
Area with the doghouse x^2 + 3x - y = 178 (that's his running around space.
Go to the dog house for a Moment
The perimeter of the doghouse and the area are equal and we are told to make them both y.
Area = y
Perimeter = y
Combined facts.
The perimeter of the Pen is three times larger than that of the dog house.
4x + 6 = 3y
The area of the Pen - The area of the doghouse = 178
x^2 + 3x - y = 178
Now what happens is that you have to juggle these two equations so they look like your answer
x^2 + 3x - y = 178
4x + 6 = 3y Subtract 3y from both sides.
4x - 3y + 6 = 0 Subtract 6 from both sides.
4x - 3y = - 6
Answer C
21. 0.25x - 1.25 - 3x + 2 = -2.75x + 0.75
22. 15/100= 0.15. 0.15•64,000= 9,600. The answer is D.
23. 1,200-300= 9,000. 1,200+300= 15,000. 9,000/15,000= 3/5. 3/5= 0.6. 60% of the building is aboveground.
24. The patterson seems to be the y=18x and when you plug 7 in to the equation, you get 126, not 128, so D is the answer.
Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
Answer:
B
Step-by-step explanation:
Just got the wrong answer on apex and it told me b was the right answer
The answer I came up with was 2.1
