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astra-53 [7]
3 years ago
8

Find the nth term in the following sequence: 10, 19, 34, 55

Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0

Answer:

The nth term of sequence is 3n^{2}+7

Step-by-step explanation:

We need to find out the general recurrence relation of sequence:

10, 19, 34, 55

if we see pattern of sequence that every square of each number 'n' is multiple of 3 and addition of 7

check this pattern by 3n^{2}+7

For n=1

3n^{2}+7

3(1)^{2}+7

3+7

10

For n=2

3n^{2}+7

3(2)^{2}+7

3\times 4+7

12+7

19

For n=3

3n^{2}+7

3(3)^{2}+7

3\times 9+7

27+7

34

And so on..

Therefore, the nth term of sequence is 3n^{2}+7

son4ous [18]3 years ago
5 0
The nth term is 3n²+7
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The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.

<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>

The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.

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Learn more about prime numbers here:

brainly.com/question/145452

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