Answer:
Process of elimination
Step-by-step explanation:
If Olive wants to choose a friend while not playing favorites, while also not being random, she has to eliminate the ones she knows she will NOT take on the trip. She can choose this by selecting the one she knows that will be best on the trip with her, depending on the situation.
Or, if Olive only has one friend, then it wouldn't be surprising that she would take that one friend on the trip, since she has no one else to choose. This way, it is not playing favorites, nor is it random. Hope this helps you!
6V^2/3
294
I used googles calculator home that helps
Given that
and
, we can say the following:

Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).
Thus, let's set what is under both square roots to be greater than 0:


Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

Now, let's look back at the function entirely, which is:

Since
is on the bottom of the fraction, we must say that
, since the denominator can't equal 0. Thus, we must exclude
from the domain.
Thus, our answer is Choice C, or
.
<em>If you are wondering why the choices begin with the
symbol, it is because this is a way of representing that
lies within a particular set.</em>
Answer:
C: 3 root 3
Step-by-step explanation:
got it right on edge
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