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3 years ago

12

Hugo lifted a total of 72 pounds in 9 attempts. Hugo lifted the same number of pounds in each attempt. how many pounds did he li

ft in each attempt?

2 answers:

____ [38]3 years ago

8 0

Hugo lifted 8 pounds in each attempt

valkas [14]3 years ago

3 0

8 attempts

72 divided by 9 equals answer

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What is the ratio of red to blue cars there were 32 red cars and 16 blue cars

Rufina [12.5K]

Answer:

2:1

32:16 is 2:1

3 0

3 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

62 in x 48 in 144 in Set Up Proportion height=

JulijaS [17]

Answer:

A geometric diagram of the two shadows and the height of the two people are shown below.

Step-by-step explanation:

5 0

3 years ago

A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0

4 years ago

Brainliest answer guaranteed <br> URGENT

UNO [17]

Answer:

$y=-6.6$ and $y=10.6$

Step-by-step explanation:

The given ellipse has equation:

$\frac{(y-2)^2}{64}+\frac{x^2}{9}=1$ .

The center of this ellipse is (h,k)=(0,2)

We use the equation: $a^2-b^2=c^2$ to determine the foci.

$\implies 64-9=c^2$

$\implies 55=c^2$

$\implies c=\pm \sqrt{55}$

The directrices are given by $y=k\pm\frac{a^2}{c}$

$y=2\pm\frac{64}{\sqrt{55}}$

$y=2\pm8.6$

$y=2-8.6$ and $y=2+8.6$

The equation of the directrices are:

$y=-6.6$ and $y=10.6$

The correct answer is D

7 0

3 years ago