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3 years ago

Solve for x with 45 degree angle & 60ft side

Mathematics

1 answer:

Alona [7]3 years ago

5 0

Answer:

x = 84.85281374 ft

Step-by-step explanation:

We know that sin theta = opposite/ hypotenuse

sin 45 = 60/x

Multiply each side by x

x * sin45 = 60/x*x

x sin 45 = 60

Divide each side by sin 45

x = 60/sin 45

x = 84.85281374 ft

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Find the slope of the graph.

slavikrds [6]

Answer:

the slope is 4/3

Step-by-step explanation:

slope is also called rise over run you start at one point and count how many spaces it is up to the next point then across

8 0

3 years ago

What is the equation in point-slope form of a line that passes through the points (−4, −1) and (5, 7) ?

Sergio039 [100]

The point-slope form:

$y-y_1=m(x-x_1)$

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-4, -1) and (5, 7). Substitute:

$m=\dfrac{7-(-1)}{5-(-4)}=\dfrac{7+1}{5+4}=\dfrac{8}{9}\\\\\boxed{y-7=\dfrac{8}{9}(x-5)}$

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3 years ago

Are:

eimsori [14]

Step-by-step explanation:

a. The mean can be found using the AVERAGE() function.

x = 272.7

b. The standard deviation can be found with the STDEV() function.

s = 39.9

c. The t-score can be found with the T.INV.2T() function. The confidence level is 0.04, and the degrees of freedom is 26.

t = 2.162

d. Find the lower and upper ends of the confidence interval.

Lower = 272.7 − 2.162 × 39.9 = 186.5

Upper = 272.7 + 2.162 × 39.9 = 358.9

4 0

3 years ago

The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

frez [133]

The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0

2 years ago

What is 132 divided by 8 using long division with the remainder (pls show the work so I can copy it pls)

adelina 88 [10]

8 goes into 13 1 time. 13-8=5. Bring down the 2. 8 goes into 52 6 times. 52-48=4. Answer is 16 remainder 4.

Check: 16x8=128, +4 remainder equals 132.

5 0

3 years ago