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crimeas [40]
3 years ago
6

Which set of angle measures could be the interior angles of a triangle? A. 15°, 48°, 27° B. 56°, 45°, 46° C. 42°, 84°, 64° D. 93

°, 29°, 58°
Mathematics
1 answer:
TEA [102]3 years ago
8 0

Answer:

D. 93°, 29°, 58°

Step-by-step explanation:

In a triangle we can only have 3 Interior angles.

The sum of the Interior angles in a triangle = 180°

Adding up the given Interior angles in the above question:

A. 15°, 48°, 27°

= 15° + 48° + 27°

= 90°

90° ≠ 180°

Option A is wrong

B. 56°, 45°, 46°

= 56 ° + 45° + 46°

= 147°

147° ≠ 180°

Option B is wrong

C. 42°, 84°, 64°

= 42° + 84° + 64°

= 190°

= 190° ≠ 180°

Option C is wrong.

D. 93°, 29°, 58°

93° + 29° + 58°

= 180°

180° = 180°

Option D is the correct Option.

Therefore, the set of angle measures that could be the interior angles of a triangle is Option D. 93°, 29°, 58°

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Step-by-step explanation:

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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

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Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

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Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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luda_lava [24]

Answer:

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Step-by-step explanation:

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distribute:

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divide by 16 to isolate x

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check:

-(-2(0.625)+1) = 9-14(0.625)

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