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lutik1710 [3]
3 years ago
7

Find the median for quiz score 9 14 8 16 13 15

Mathematics
2 answers:
Lena [83]3 years ago
8 0

So you first have to order them least to greatest, which would be : 8 , 9 , 13, 14 , 15, 16. Since the number of numbers is even, average the 2 middle numbers. This is 13 + 14 divided by 2 or 13.5.

weeeeeb [17]3 years ago
7 0

It's 13.5 because you put them in order and then you have 13 and 14 you add them together and then divide by 2

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Which equation represent the line that passes through the points (-4,3) and (2,-12)
Lina20 [59]
I'm pretty sure it's: 5x + 2y = –14
5 0
3 years ago
How many times larger is 3.6 x 106 than 7.2 x 105?
Kazeer [188]
- 374.4 is the answer


Explanation

3.6 * 106 = 381.6

7.2 * 105 = 756

Subtract 756 from 381.6
= - 374.4


Hope this helps :)

Have a great day !
4 0
3 years ago
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
En el experimento Extraer una carta de una baraja española se consideran estos sucesos: A= 《Salir as 》 B= 《salir bastos 》 Calcul
Ganezh [65]

Answer:

They are compatible

Step-by-step explanation:

The first thing is to say that an "ace" and that it is a "coarse"

"ace" is card number 1. Group A

"coarse" is a type of the deck, found from number 1 to card 13. Group B

Thus:

 Calculate A U B:

1 to 13 + 1 of the other types of cards in the deck.

At intersection B:

1 of "coarse"

Therefore, if group A is compatible with group B

7 0
3 years ago
188=4(7v-2) <br><br> solve for v?
frutty [35]
188=28 v-8
28 v=188+8
28 v += 196
v=7
there u go !!!!
7 0
3 years ago
Read 2 more answers
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