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never [62]
3 years ago
10

15x^2 + 41x + 28 STEP BY STEP ANSWER PLSSS​

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

253+41x

Step-by-step explanation:

first evaluate the power of 15

then add the number 225+28

then the answer will be 253+41x

maria [59]3 years ago
7 0

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

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a boat cost 12,050 and decreases in value by 12% per year. How much will the boat be worth after 9 years
Eduardwww [97]
Given:
Cost = 12,050
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</span> </span> <span> 6 <span>          6,359.17               </span>12% <span>            763.10 </span> <span>     5,596.07
</span> </span> <span> 7 <span>          5,596.07               </span>12% <span>            671.53 </span> <span>     4,924.54
</span> </span> <span> 8 <span>          4,924.54               </span>12% <span>            590.94 </span> <span>     4,333.60
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The boat will be worth $3,813.56 after 9 years.

Depreciation = beginning cost x depreciation rate
Ending cost = beginning cost - depreciation

Depreciation is the wear and tear of an object that decreases its value.</span></span></span></span>
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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