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Morgarella [4.7K]
3 years ago
6

Solve for s. s+24=90

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0
S + 24 = 90

This is a one-step problem. so, all you have to do is subtract 24 on both sides:

s + 24 - 24 = 90 - 24

s = 66

Check your work:

66 + 24 = 90

90 = 90

Hope this helps!!
~Kiwi
leonid [27]3 years ago
5 0
Step 1. Subtract 24 from both sides
s = 90 - 24
Step 2. Simplify 90 - 24 to 66
s = 66
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in a tidal river, the time between high and low tide is 7.6 hours. At high tide the depth of water is 17.2 feet, while at low ti
Lady_Fox [76]
Alright, so the difference between tidal heights is 12.6 ft. right? For every integer cos(x) is multiplied, say a*cos(x) the amplitude doubles. So then, (1/2)=(n/12.6) will gives us a value for a that will match the differences in tidal height. a=6.3. Now let's say that 2pi will give us a full cycle from high to low back to high again. If 12:00 noon is our high, it takes 15.2hrs to complete a cycle back to high again. 2pi = 6.28 roughly, and we know that is less than our midpoint in a whole cycle, 7.6 hrs. Also, for every value k>1 in cos(kx), this increases the frequency of waves in a given period. So it seems that we need a value of k less than 1. So we can lower the frequency to match the cycle we are looking for, which is to come back to 17.7 ft by 15.2hrs. So to find our value k we divide 2pi by 15.2. This is 0.41. We do it that way based on the ratio for the standard period to what we need, which is a number that can get us to 15.2. So far we have f(t) = 6.3cos(0.41x). Now the problem we have now is that we are not at our height for max, nor our min, even though our wave matches the difference between them, we are between 6.3 and -6.3 so far. so for every value of c in cos(x)+c, this adds to the height cos starts on the y-axis. Since we are at 6.3 already, all we need to do is subtract 6.3 from 17.6 to get c. So C is 11.3 and our final equation is f(t)=6.3cos(0.41x)+11.3. This gives our tides in 15.2 hr periods, starting at 12 noon = x=0, with extremes at intervals of 7.6 hours. Let me know if you have any more questions about it, it's kind of rough to explain. We transformed by f(t)=a*cos(kx)+c altogether, but I thought it might help to separate each value independently.
4 0
3 years ago
Read 2 more answers
Find the absolute maximum and minimum of the function on the given domain. f (x comma y )equals 8 x squared plus 7 y squared on
pickupchik [31]

Answer:

the maximum value is 7

The minimum value is 0

Step-by-step explanation:

Step One : Interpret the question

       The above question can be written like

The Equation

            f(x,y) = 8x^2 +7y^2

The diagram of the triangular plate and the bounded lines is shown on the first uploaded image

          From the diagram  f(0,0) = 8(0)^2 +7(0)^2 =0

                                          f(1,0) =8(1)^2 + 7(0)^2 = 8

                                          f(0,1) =8(0)^2 + 7(1)^2 = 7

Partial differentiation of the equation w.r.x

                           A =\frac{\delta f}{\delta x }  = 16x

 Partial differentiation of the equation w.r.y

                          B =\frac{\delta f}{\delta y }  = 14y            

Looking at the diagram the maximum value is 7 i.e  at (x , y) = (0,1)

The minimum value is 0 i.e  (x , y) = (0,0)

3 0
3 years ago
Find the measure of BE step by step ​
Zigmanuir [339]

Answer:

BE = 49

Step-by-step explanation:

In triangle BDC

  65^2=56^2+BD^2

  65^2-56^2=BD^2

  4225-3136=BD^2

  1089=BD^2

   33=BD

In triangle FDE

    65^2=63^2+DE^2

    4225-3969=DE^2

    256 = DE^2

    16=DE

since ED+DB=BE

THEREFORE

      16+33=BE

         49=BE

6 0
3 years ago
15. I had 180 mL of water in a measuring cylinder. I added a stone. The reading is now 195 mL. What is the volume of the stone?​
alexira [117]

Answer: 15 mL

Step-by-step explanation:

Before the stone the reading was 180 mL

When the stone was added the reading rose to 195 mL

So, we subtract them both, this will give us the volume of the stone

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alukav5142 [94]

Answer:

\huge{ \boxed{ \tt{ \frac{ 7}{4} }}}

Step-by-step explanation:

\text{Let \: the \: points \: be \: A \: and \: B}

\sf{A \:( \: 0 \:,  - 5 \: )  \longrightarrow{ \: (x1 \:, y1)}}

\sf{B(4 \:, 2) \:  \longrightarrow{ \:( x2 \:, y2)}}

\underline{ \text{Finding \: the \: slope} }:

\boxed{ \sf{Slope =  \frac{y2 - y1}{x2 - x1}}}

\sf{➳ \: Slope =  \frac{2 - ( - 5)}{4  - 0}}

\sf{➳ \: Slope =  \frac{ 2 + 5}{4} }

\sf{➳ \: Slope =  \frac{7}{4} }

\text{Hope \: I \: helped!}

\text{Best \: regards!}

~\text{TheAnimeGirl}

3 0
4 years ago
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