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vitfil [10]
3 years ago
5

What's The Improper Fraction To 1 and 2/3

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
5/3 is the improper fraction... you multiply the denominator with the whole number then add the numerator and keep the same denominator
dsp733 years ago
4 0
5/3 is the improper fraction
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Find the value of x. Round to the nearest tenth.
goblinko [34]

Answer:

19.7

Step-by-step explanation:

37-17.3=19.7 which would be the value of x

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John asked 60 people to name their favourite fruit here are his results
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Pears 15-30
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Kiran starts at 9:00 am by bicycle to reach office. She cycles at the speed of 8 km/hour and reaches the office at 9:15 am. By h
Ivenika [448]

Answer:

v = 12 km/h

Step-by-step explanation:

To find how much she should increase the speed first we need to find the distance traveled:

d = v*t

Where:

d: is the distance traveled =?

v: is the velocity = 8 km/h

t: is the time = 15 min (9:00 to 9:15)

d = v*t = 8 km/h*15 min*\frac{1 h}{60 min} = 2 km  

Now, we can find the speed:

v_{f} = \frac{d}{t} = \frac{2 km}{10 min*\frac{1 h}{60 min}} = 12 km/h

Therefore, she should increase the speed to 12 km/h to reach the office at 9:10 am.

I hope it helps you!

6 0
3 years ago
You mix 2 and one half
Blizzard [7]

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wpild be about 3 to 1 juice to pop

7 0
3 years ago
A popular charity used 31% of its donations on expenses. An organizer for a rival charity wanted to quickly provide a donor with
Law Incorporation [45]

Answer:

Reject the null hypothesis. There is sufficient evidence to conclude that the mean is less than 31%.

Step-by-step explanation:

In this case we need to test whether the popular charity has expenses that are higher than other similar charities.

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The popular charity has expenses that are higher than other similar charities, i.e. <em>μ </em>> 0.31.

<em>Hₐ</em>: The popular charity has expenses that are less than other similar charities, i.e. <em>μ </em>< 0.31.

As the population standard deviation is not known we will use a t-test for single mean.

Compute the sample mean and standard deviation as follows:

\bar x=\frac{1}{n}\sum X=\frac{1}{10}\cdot[0.26+0.12+...+0.26]=0.238\\\\s= \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 0.0674 }{ 10 - 1} } =0.08654\approx 0.087

Compute the test statistic value as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{0.238-0.31}{0.087/\sqrt{10}}=-2.62

Thus, the test statistic value is -2.62.

Compute the p-value of the test as follows:

 p-value=P(t_{\alpha, (n-1)}

                =P(t_{0.05,9}

*Use a t-table.

Thus, the p-value of the test is 0.014.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.014 < α = 0.05

The null hypothesis will be rejected at 5% level of significance.

Thus, concluding that there is sufficient evidence to conclude that the mean is less than 31%.

7 0
4 years ago
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