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solong [7]
3 years ago
14

A school has 360 students, 4/9 of whom are boys. How many boys is that? How many girls?

Mathematics
2 answers:
matrenka [14]3 years ago
6 0
The answer is 160. There are 160 boys in the school. Take 360 divide by 9, then multiply by four. 


levacccp [35]3 years ago
3 0

360 *4 = 1440 / 9 =160 boys

360-160 = 200 girls

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Sorry again but i'm having trouble on this one
Lisa [10]

Answer:

m∠PNO = 60°

m∠O = 33°

Step-by-step explanation:

∡NPO is 87° because it's a vertical angle with the 87° angle

3) ∡PNO is supplementary to the 120° angle (they must add to 180°)

4) m∠O = 180 - (60 + 87) = 33

5 0
2 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
2 years ago
Help me with this please​
ololo11 [35]
I think the answer is t
3 0
3 years ago
Read 2 more answers
What is 462 times 3 with or with out a remained
Nastasia [14]
1,386
 is the answer hope this helped
5 0
2 years ago
Read 2 more answers
Suppose a triangle has 2 sides of length 3 and 4 and that the angle between these two sides is 60 degrees. what is the length of
shusha [124]

Answer:

\boxed{b.\:\:\:\sqrt{13}}

Step-by-step explanation:

Let the third side of the triangle be h\: units.


We can apply the cosine rule to find h.


h^2=3^2+4^2-2(3)(4)\cos(60\degree)

We evaluate to obtain;

\Rightarrow h^2=9+16-24(\frac{1}{2})


\Rightarrow h^2=25-12


\Rightarrow h^2=13

We take the positive square root of both sides to obtain;

\Rightarrow h=\sqrt{13}


The correct answer is B.

8 0
3 years ago
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