Answer:
<h2>A. R=1098.7ft</h2><h2>B. H=274.7ft</h2>
Step-by-step explanation:
<em>"The question is not complete, here is the complete question</em>
<em> The range R and the maximum height H of a projectile fired at an inclination θ to the horizontal with initial speed v0 are given by the formulas below, where g≈32.2 feet per second per second is the acceleration due to gravity. Complete parts A and B.</em>
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<em>A. Find the range R if the projectile is fired at an angle 45° to the horizontal with an initial speed of 190 ft per second</em>
<em>B. Find the maximum height H if the projectile is fired at angle 45° to the horizontal with an initial speed of 190 ft per second"</em>
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<u>Solution</u>
A. given the expression for Range R
substitute v= 190 ft/sec and ∅=45°

B. . given the expression for maximum height
substitute v= 190 ft/sec and ∅=45°

Answer:
15.8
74.2
Step-by-step explanation:
Call the two angles A and B
A = B + 58.4 Substitute for A
A + B =90
B + 58.4 + B = 90 Combine like terms
2B + 58.4 = 90 Subtract 58.4
2B = 90 - 58.4
2B = 31.6 Divide by 2
B = 15.8
A = 15.8 + 58.4 Fin A
A = 74.2
Answer:

Step-by-step explanation:
To avoid confusion, distribute the negative amongst all terms in the second set of parentheses.
I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.
Given that the sum of the three interior angles of a triangle is equal to 180°, we can formulate the following equation:
2x + 1 + 2x + 93 = 180
4x + 94 = 180 (Adding like terms)
4x = 180 - 94 (Subtracting 94 from both sides of the equation)
4x = 86
x= 86/4 (Dividing by 4 on both sides of the equation)
x= 21.5
Replacing in the angles we have:
Angle 2x + 1 ---> 2(21.5) + 1= 44
Angle 2x ---> 2(21.5) = 43
The angles of the triangle are 43, 44 and 93.