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alukav5142 [94]
4 years ago
14

A flower vase, in the form of a hexagonal prism, is to be filled with 512 cubic inches of water. Find the height of the water if

the wet portion of the flower vase and its volume are numerically equal.
Mathematics
1 answer:
wel4 years ago
4 0
Volume of the base = base area x height
512 = 3√3 / 2 a²h
h = 197/a², where a is the length of the side of the hexagonal base.
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A water balloon is tossed into the air. The function h(x)=-0.5(x-4)squared +9 gives the height, in the feet, of the balloon from
NNADVOKAT [17]

Answer:

No, the maximum height that the balloon can reach is 9ft.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

The function h(x) =-0.5(x-4)² +9, is a Quadratic Function in the Vertex form.

Vertex form: f (x) = a(x - h) 2 + k

Where:

  • (h, k) is the vertex of the parabola-
  • h is the horizontal shift (how far left, or right, the graph has shifted from x = 0).  
  • k represents the vertical shift (how far up, or down, the graph has shifted from y = 0).  

In this case a = -0.5, it means that the parabola opens downward and has a maximum point at the vertex.

So, the maximum height that the balloon can reach is k=9ft.

9 ∠ 12

The balloon will not hit the ceiling 12 ft above the pool.

Feel free to ask for more if needed or if you did not understand something.

8 0
4 years ago
Fr.ee points have a good day
Masja [62]

Answer:

Thank you Have a good day

8 0
3 years ago
Suppose that 16 inches of wire costs 64 cents. At the same rate, how many inches of wire can be bought for 36 cents?
valina [46]

Answer:

<u>8 inches of wire can be bought for 36 cents.</u>

<u>8 inches of wire can be bought for 36 cents.Step-by-step explanation:</u>

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5 0
3 years ago
Read 2 more answers
If the center thickness of a lens variés more than 0.150 millimeter from the target thickness of 5.000 millimeters, the lens can
Mice21 [21]

Answer:

All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters

Step-by-step explanation:

Let

x -----> values for the center thickness of the lens

we know that

The absolute value that represent this problem is

\left|x-5,000\right|\le 0.150

Solve the absolute value

First case (positive)

+(x-5,000)\le 0.150

Adds 5,000 both sides

x\le 0.150+5,000

x\le 5,000.15\ mm

Second case (negative)

-(x-5,000)\le 0.150

Multiply by -1 both sides

(x-5,000)\ge -0.150

Adds 5,000 both sides

x\ge -0.150+5,000

x\ge 4,999.85\ mm

therefore

The extreme acceptable values for the center thickness of the lens is the interval [4,999.85,5,000.15]

All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters

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Turn 42/12 into a mixed number
bulgar [2K]
Start by simplifying by dividing both numerator and denominator ;
21/11
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