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NikAS [45]
3 years ago
9

If the measure of angle 1 is 110 and the measure of angle 3 is (2x+10), what is the value of x

Mathematics
2 answers:
givi [52]3 years ago
6 0
< 1 and < 3 are vertical angles....they are equal

2x + 10 = 110
2x = 110 - 10
2x = 100
x = 100/2
x = 50 <===
katrin2010 [14]3 years ago
4 0
2x+10=110
2x=100
x=50
A. 50 is correct
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Answer:

5.76

Step-by-step explanation:

18% of 32

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=18/100 x 32

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In a certain town, 22% of voters favor a given ballot measure. For groups of 21 voters, find the variance for the number who fav
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c. 4.6

       

21 X .22= 4.6

       

Calculating the variance requires finding the product of 21 and 22%. To make this easier we convert 22% into it's decimal form and construct the equation. To back check this answer we can use 10% of 21 voters which equals 2.1% then double that amount to reach 4.2%, knowing that we now have a close approximation of the variance we can eliminate answers a, b, and d, leaving c as the only logical choice.

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3 years ago
The original price for a jacket was 124.95. It is on sale for 20% off. Witch of the following gives the best estimate of the sav
d1i1m1o1n [39]
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7 0
3 years ago
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Una persona toma 7/8 de medicina cuánto toma en tres veces al día<br><br><br>​
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5 0
3 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

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5 0
3 years ago
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