Question

Please help plleeassee

Answer 1

What is even happening lol

Answer 2

Answer:

1) f(n) =f(n-1) + 22

2) f(n)=f(n-1) + 21

3)f(n)=6*f(n-1)

Step-by-step explanation:

1) The first series is given as 11,33,55,77....

Also, f(1)=11

Now, f(n)=f(n-1) + 22

So, f(2)=f(1) + 22

           =11 + 22

           =33

f(3)=f(2) + 22

    =33 + 22

    =55

And so on.

2) The second series is given as -18,3,24,45....

Also, f(1)=-18

Now, f(n)=f(n-1) + 21

So, f(2)=f(1) + 21

           =-18 + 21

           =3

f(3)=f(2) + 21

    =3 + 21

    =24

And so on.

3) The third series is given as -18,-108,-648,-3888....

Also, f(1)=-18

Now, f(n)=6*f(n-1)

So, f(2)=6*f(1)

           =6*(-18)

           =-108

f(3)=6*f(2)

    =6*(-108)

    =-648

And so on.