Considering that the powers of 7 follow a pattern, it is found that the last two digits of are 43.
<h3>What is the powers of 7 pattern?</h3>
The last two digits of a power of 7 will always follow the following pattern: {07, 49, 43, 01}, which means that, for , we have to look at the remainder of the division by 4:
- If the remainder is of 1, the last two digits are 07.
- If the remainder is of 2, the last two digits are 49.
- If the remainder is of 3, the last two digits are 43.
- If the remainder is of 0, the last two digits are 01.
In this problem, we have that n = 1867, and the remainder of the division of 1867 by 4 is of 3, hence the last two digits of are 43.
More can be learned about the powers of 7 pattern at brainly.com/question/10598663
Answer:
A=5/2a^2(5+2√5)
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
x + 3 1/8 = 7 1/8
-3 1/8 | -3 1/8
-------------------------
x = 4
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