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3 years ago

Find the 50th term of 0,3,6,9

1 answer:

7 0

$\text{a}_1=0 \ \text{and} \ \text{a}_2=3\\\\\text{r}=\text{a}_2-\text{a}_1=3-0=3\\\\\text{a}_{50}=\text{a}_1+49\text{r}=0+49\cdot3=0+147=147\\\\\huge\boxed{\text{a}_{50}=147}$

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Solve this equation:<br>9+3×2^2-1×4

inessss [21]

9 + 3 × 2² - 1 × 4

= 9 + 3 × 4 - 1 × 4

= 9 + 12 - 1 × 4

= 21 - 1 × 4

= 21 - 4

= 17

Follow the order of PEMDAS, where,

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

___

Hope it helps ⚜

5 0

2 years ago

Read 2 more answers

The equation 4.50 the equation 3d + 2=29 can be used to find the height of a bean plant d days after it was purchased how many d

anygoal [31]

Answer: 9 days

Step-by-step explanation: you have to do the reverse

3d+2=29 Subtract 2 from both sides

3d=27 Divide 27 from both

d=9 The plant was planted 9 days ago

6 0

3 years ago

Determine which ordered pairs fall on the graph of f(x) = -2x-1 Show all of your work for each ordered pair. Ordered Pairs: (1,1

LiRa [457]

Answer:

(1, 1) is the only one on the graph

Step-by-step explanation:

To determine if an ordered pair lies on the graph, substitute the x-coordinate of the ordered pair into f(x) and evaluate. If the value equals the y-coordinate of the ordered pair then it lies on the graph

f(1) = (2 × 1) - 1 = 2 - 1 = 1 ⇒ (1, 1) lies on graph

f(- 1) = (2 × - 1) - 1 = - 2 - 1 = - 3 ≠ - 4 ⇔ (- 1, - 4 ) not on graph

f(- 2) = (2 × - 2) - 1 = - 4 - 1 = - 5 ≠ - $\frac{1}{8}$ ⇒ (- 2, - $\frac{1}{8}$ ) not on graph

f(0) = (2 × 0) - 1 = 0 - 1 = - 1 ≠ $\frac{1}{2}$ ⇒ not on graph

8 0

4 years ago

The vertices of a backyard are W(10,30),X(10,100),Y(110,100),Z(50,30). The coordinates are measured in feet. The line segment XZ

MariettaO [177]

Given vertices W(10,30), X(10,100), Y(110,100), Z(50,30) of a backyard, find distances WX, XY, YZ, ZW and XZ:

1. $WX=\sqrt{(10-10)^2+(30-100)^2}=\sqrt{70^2}=70\ ft;$

2. $XY=\sqrt{(110-10)^2+(100-100)^2}=\sqrt{100^2}=100\ ft;$

3. $YZ=\sqrt{(110-50)^2+(100-30)^2}=\sqrt{60^2+70^2}=10\sqrt{85}\ ft;$

4. $ZW=\sqrt{(50-10)^2+(30-30)^2}=\sqrt{40^2}=40\ ft;$

5. $XZ=\sqrt{(10-50)^2+(100-30)^2}=\sqrt{40^2+70^2}=10\sqrt{65}\ ft.$

Then:

1. the area

$A_{WXZ}=\sqrt{\frac{70+40+10\sqrt{65}}{2}\\\cdot (\frac{70+40+10\sqrt{65}}{2}-70)\cdot (\frac{70+40+10\sqrt{65}}{2}-40)\cdot (\frac{70+40+10\sqrt{65}}{2}-10\sqrt{65})}=\\ \\=1400\ ft^2.$

2. the area

$A_{XYZ}=\sqrt{\frac{100+10\sqrt{85}+10\sqrt{65}}{2}\cdot (\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-100)}\cdot\\ \\\cdot\sqrt{(\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-10\sqrt{85})\cdot (\frac{100+10\sqrt{85}+10\sqrt{65}}{2}-10\sqrt{65})}=3500\ ft^2.$

Then

$\dfrac{A_{XYZ}}{A_{WXZ}}=\dfrac{3500}{1400}=2.5$ times greater.

6 0

4 years ago

Sally has two coins. The first coin is a fair coin and the second coin is biased. The biased coin comes up heads with probabilit

coldgirl [10]

Answer:

50%

Step-by-step explanation:

''What is the probability that she selected the biased coin?”

When we have n possible outcomes of an event and all of them have the same probability of appearance, then in theory each possibility has a probability 1/n of being the result of the event.

In this case the event is choosing randomly a coin out of 2, so no matter what the biased coin is or the results we get when we toss it, the probability of choosing the biased coin is ½ = 0.5 or 50%.

4 0

3 years ago