Question

The smaller of two consecutive even integers is two more than half of the greater. find the two integers.

Answer 1

Greetings and Happy Holidays! 

Let x represent the smaller, even integer.
Let (x+2) represent the larger, even integer.

We can create an algebraic equation to solve for the numbers:
$x=\frac{(x+2)}{2}+2$

Simplify:
$x=\frac{1}{2}x+1+2$

$x=\frac{1}{2}x+3$

Add $\frac{-1}{2}x$ to both sides:
$(x)+(\frac{-1}{2}x)=(\frac{1}{2}x+3)+(\frac{-1}{2}x)$

$(\frac{1}{2}x)=3$

Divide both sides by $\frac{1}{2}x$
$\frac{\frac{1}{2}x}{ \frac{1}{2}}=\frac{3}{\frac{1}{2}}$

$x=\frac{3}{1}(2)$

$x=\frac{6}{1}$

The Answer Is:
$\boxed{x=6}$
and
$x+2=6$
$\boxed{x=8}$

The two consecutive even integers are 6 and 8.

I hope this helped!
-Benjamin