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nekit [7.7K]
3 years ago
15

duuuudes need help asap FAST lil' sister cant fail;A rectangular horseshoe pit is 53 inches long and 32 inches wide. What is the

area of the horseshoe pit?
Mathematics
2 answers:
Molodets [167]3 years ago
5 0
The area is 1696 area of a rectangle is always and will be L x W 

valina [46]3 years ago
3 0
Hi there! Area = Length×Width. Where the length is 53 inches and the width is 32 inches. We multiply 53 inches by 32 inches. 53 inches × 32 inches = 1696. Therefore, the area of the horseshoe pit is 1696 inches². Hoped I helped ♥♥♥
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The area of a rectangle is 259 cm2 and its lenght is 18.5 cm find
crimeas [40]

The breadth of rectangle is 14 cm

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<em><u>Solution:</u></em>

Given that,

Area of rectangle = 259 square centimeter

Length of rectangle = 18.5 cm

<em><u>The area of rectangle is given by formula:</u></em>

Area\ of\ rectangle = length \times breadth

<h3><u>Find the breadth:</u></h3>

Substitute the given values in above formula:

259 = 18.5 \times breadth\\\\breadth = \frac{259}{18.5}\\\\breadth = 14

Thus breadth is 14 cm

<h3><u>Find the perimeter:</u></h3>

The perimeter of rectangle is given by formula:

Perimeter = 2(length + breadth)

Substitute the given values in above formula:

perimeter = 2(18.5+14)\\\\perimeter = 2(32.5)\\\\perimeter = 65

Thus perimeter of rectangle is 65 cm

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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