Answer:
Nope, sorry.
Step-by-step explanation:
Answer:
1) 500 2) $ 1000 debt 3) $350 4) $2500 debt
Step-by-step explanation:
profit = .5x -250
1) O = .5x -250
250 = .5x
500 = x number to break even
2) f(900) = .5 (900) -250 = $200
from the graph g(200) = total debt = $1000
3) f(x) = -75 = .5x-250 results in x = $ 350
4) f(500) = .5(500) - 250 = 0
from the graph, this corresponds to total debt g (f(500) = $2500 debt
A= (h(a+b))/2
multiply each side by 2
2A = (h(a+b))
divide each side by h
2A/h = a+b
subtract a from each side
2A/h -a = b
The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866
I’m pretty sure the answer is 60!!!!
