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3 years ago

What are 3 consecutive integers that have a sum of 234

Mathematics

1 answer:

Colt1911 [192]3 years ago

3 0

$n+n+1+n+2=234\\
3n+3=234\\
3n=231\\
n=77\\
n+1=78\\
n+2=79$

77,78,79

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2 years ago

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Check your answer by plugging -6 in for the x in the original problem:

$\frac{2}{3} - \frac{1}{x} = \frac{5}{6}$ Plug in -6 for x
$\frac{2}{3} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{2}{3}$ to $\frac{4}{6}$ so all denominators are the same
$\frac{4}{6} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{1}{-6}$ to $\frac{-1}{6}$ for easier work
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2 years ago

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Misha Larkins [42]

Answer:

that would be 7.33

Step-by-step explanation:

sorry it's 66

I divided 3 by 22 instead of multiplying

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2 years ago

Read 2 more answers