Answer:
6.
Step-by-step explanation:
Source: Desmos.
When the points are plotted, the shape is a polygon. The polygon has 6 sides.
Picture represents the polygon shape, and its sides
In the figure, the horizontal lines are parallel and AB = BC = CD. If LM = 3 Find JM? A. 12 B. 6 C. 3 D. 9
1 answer:
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Cos(x) = sin(x + 20o) Use the double cos angle formula
Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)
1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.
1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)
0.65798 = tan(x) * 0.939692 Divide by cos(20)
tan(x) = 0.65795/0.939692
tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)
x = tan-1(0.70021)
x = 35 degrees as expected.
Problem Two
The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.
Let A = 25
Let C = 65
A
Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.
sin(25)/sin(65) = 0.4663 Answer
B
Sin(90 - C) = Sin(A)
Tan(90 - A) = Tan(C)
So the question becomes Cos(A) = Tan(C) / sin(A)
Cos(25) = Tan(65)/Sin(25)
0.906 = ? 5.07 This statement isn't true.
C
Sin(65) = Cos(25)/Tan(65)
.906 = 0.4226 C is not the correct answer.
D
D isn't true. The tan does not relate that away. You can find it for yourself.
Cos(A) = Tan(C) You should get 0.906 = 2.14
E
Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.
Problem 3
The diagram below is for this problem. Cos(x) = 50/100 = 0.5
x = cos-1(0.5)
x = 60 degrees.
Part 2
Sin(60) = opposite / hypotenuse
opposite = sin(60) * hypotenuse
opposite = 86.61 Be sure and round this to whatever the question says to round it to.
Answer:
option C
c. least: $101
greatest: $1001
Step-by-step explanation:
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.
Sum of 10 prizes = 5510
100 is the difference. there is a common difference d=100
So its a arithmetic sequence
the sum formula for arithmetic sequence is
Sn = 5510, n=10 n d= 100 we need to find out first term a1
5510 = 5 (2a1 + 900)
5510 = 10a1 + 4500
Subtract 4500 on both sides
1010= 10a1
divide by 10 on both sides
a1 = 101
so first term that is least term is 101
To find out greatest term we use formula
a(10) = 101 + (10-1)100
= 101 + 900= 1001
greatest is 1001