Find the value of bx9 when b=8

Leokris [45]

Hi there,

2 (4x - 11) = 10
4x - 11 = 5
4x = 5 + 11
4x = 16 then divide both sides by 4
16 divided by 4 = 4

Hope this helps :)

3 0

3 years ago

Kylie and Ethan have each saved some money. I’m their savings, each coin is worth leas then 50 cents and each bill is less then

timofeeve [1]

Answer:

Kylie could have a $5 bill and seven quarters while Ethan could have two $1 bills and forty pennies.

Step-by-step explanation:

Since Kylie has seven quarters, that is seven multiplied by the value of the quarter, a quarter is 25 cents. So 7 x 25 = 125 OR $1 and 25 cents. Leaving Kylie with a total of $7 and 25 cents with the addition of the $5 bill.

Ethan has two $1 bills and forty pennies, forty multiplied by the value of the penny, a penny is 1 cent. So 40 x 1 = 40 OR 40 cents. Leaving Ethan with $2 and 40 cents with the addition of the two $1 bills from earlier.

Ethan has more bills and coins than Kylie and yet still has less money than Kylie.

7 0

3 years ago

HELP ME!!!! ASAP!!! PLEASE!!!<br> Explain why the equation (x-6)^2-3=13 has two solutions.

Yuki888 [10]

It has 2 equations bc it hasq 2 part

3 0

3 years ago

Read 2 more answers

Multiply 4 and 7. Then, divide by q.

Makovka662 [10]

Answer:

28/q

Step-by-step explanation:

4 times 7 equals 28 and then divide 28 by q

5 0

2 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

2 years ago