The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
<h3>Reflection of functions and coordinates</h3>
Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates <u>changes position but are negated.</u>
Given the exponential function below
f(x) = 5(0.8)^x
If the function f(x) is reflected over the x-axis, the resulting function will be
-f(x)
This means that we are going to negate the function f(x) as shown;
f(x) = -5(0.8)^x
Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
Learn more on reflection here: brainly.com/question/1908648
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Answer:
C. f(-1) =12
Step-by-step explanation:
f(x)= 3x^2+9
Let x=-1
f(-1) = 3(-1)^2 +9
= 3(1)+9
= 3+9
= 12
f(-1) =12
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
253. First, I squared 8, to get 64, then multiplied that by 12. I subtracted 9 from this because 3x3 is 9 to get 759. Then, divide this by 3 to get 253. Hope this helped!
