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Daniel [21]
3 years ago
9

Help please! i don't know what to do

Mathematics
1 answer:
Serhud [2]3 years ago
8 0
I hope this helps you



9/9+18=x/x+10


9/27=x/x+10


1/3=x/x+10

3x=x+10

x=5


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Statement 1: If parallel lines have a transversal, then corresponding angles are congruent. Statement 2: A line has an infinite
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3 years ago
I NEED HELP WITH THIS ASAP! ITS DUE IN 20 MINS
amm1812

Answer:

b

Step-by-step explanation:

I pretty sure it b can u plz mark as brlainlest sorry if wrong try b

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3 years ago
How do you simplify that question? For algebra 1.
motikmotik
\left( \sqrt{x^{-3}} \right)^5 =  \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }


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\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}

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Solve for x:<br> AD bisects ZBAC<br> A
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2 years ago
Write the equation of a circle whose center is at (3,-2) and has a radius of 11.<br>Show your work!
Viefleur [7K]

Answer:

(x - 3)^{2} + (y + 2)^{2} = 121

Step-by-step explanation:

The equation of a circle has the following format:

(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}

In which r is the radius and the centre is the point (x_{0}, y_{0})

In this question:

Center at (3,-2), so x_{0} = 3, y_{0} = -2

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Then

(x - 3)^{2} + (y - (-2))^{2} = 11^{2}

(x - 3)^{2} + (y + 2)^{2} = 121

3 0
3 years ago
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