Question

Write the equation of a circle whose center is at (3,-2) and has a radius of 11.Show your work!

Answer 1

Answer:

$(x - 3)^{2} + (y + 2)^{2} = 121$

Step-by-step explanation:

The equation of a circle has the following format:

$(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}$

In which r is the radius and the centre is the point $(x_{0}, y_{0})$

In this question:

Center at (3,-2), so $x_{0} = 3, y_{0} = -2$

Radius 11, so $r = 11$

Then

$(x - 3)^{2} + (y - (-2))^{2} = 11^{2}$

$(x - 3)^{2} + (y + 2)^{2} = 121$