Answer:
what problem
Step-by-step explanation:
????/
Answer:
13
Step-by-step explanation:
(180-(11v+15)+9v-8+6v-9=180
4v+148=180
4v=52
v=52/4
=13°
Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
To Learn more about similar flagpole questions:
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You need to figure out how many square feet one paint can will be able to paint, then take the 24 square feet and divide it by the how much the paint can can paint, then you’ll have how many paint cans you need
Answer:
B
Step-by-step explanation:
End points coincide and we also know the opposite angles are equal