Answer: 1.53
Step-by-step explanation:
The given data : 4, 4, 4, 4, 6, 8
Number of data values : n= 6
The mean value of the given data will be :-

The formula to find standard deviation:_
![\sqrt{\dfrac{\sum(x-\overline{x})^2}{n}]](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cdfrac%7B%5Csum%28x-%5Coverline%7Bx%7D%29%5E2%7D%7Bn%7D%5D)
Now,

The standard deviation will be :-

The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
C, the sum of the decimals is greater than one, meaning they shade more than one.
90? there’s a 45 degree angle at the bottom left and it looks like the same angle as x and y
Not A because regular means all sides are equal.
B has to be the answer because the others are not.
Not C because a right triangle is not regular, i.e. and equilateral triangle.
Not D because a rectangle has different side lengths.