4(x-2/3) = -18
4x - 8/3 = -18
4x = -54/3 + 8/3
4x = -46/3
x = -46/3 * 1/4
x = -46/12
x = -23/2
2x = -23/2 * 2
2x = -46/2
2x = -23
Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Answer:
B. 4t=27
Step-by-step explanation:
let t be the price of one ticket,
since there are 4 people buying tickets in total, the price of 4 tickets would be 4t.
so
.