Step-by-step answer:
For relatively small denominators, the easiest way is to multiply the two denominators AND divide by the highest common factor (HCF).
For example, adding 5/24+3/16
24*16 = 384
(use a calculator if necessary, for mental calculation, 24*16=20^2-4^2=400-16=384 ).
The highest common factor (HCF) is 8, since 24/8=3, 16/8=2, 3 and 2 do not have any more common factors, so it is the HCF.
The lowest common multiple (LCM) is then 384/8 = 48
For someone good at factoring, we see that the factors are:
24={2^3,3}
16={2^4} = {2^3,2}
so the LCM is either 16*3=48, or 24*2=48.
4 is paired withe 6 to give 24 ..because 6X4 =24 ..
Hope it helps !!!
A. 355, it's the smallest amount you need.
b. 71*2*2.5... don't think this is right, I'm so sorry
The first tank contains
486 gal - (4 gal/week) <em>t</em>
gal of water after <em>t</em> weeks.
Similarly, the second tank contains
648 gal - (7 gal/week) <em>t</em>
gal of water.
The tanks hold the same amount of water when these two amounts are equal:
486 gal - (4 gal/week) <em>t</em> = 648 gal - (7 gal/week) <em>t</em>
(7 gal/week) <em>t</em> - (4 gal/week) <em>t</em> = 648 gal - 486 gal
(3 gal/week) <em>t</em> = 162 gal
<em>t</em> = (162 gal) / (3 gal/week)
<em>t</em> = 54 weeks
Answer:
c=rd/s
Step-by-step explanation:
r=cs/d
Times both sides by d
rd=cs
switch it around so c is on the left
cs=rd
divide both sides by s
c=rd/s
