Square with the height of 10m,length of 3m and the thickness of 1cm,what is the volume of the square

- 7th Grade Work - Please write your answer like this: 1. 2. 3.

Naily [24]

Answer:

1. -4x < 8

2. 4x < 8

3. When something is done to one side of the equation, the same thing must be done to the other side. Dividing each side by -4 in part A would cause the sign to flip because the sign is always flipped when dividing by a negative. Because 4 in 4x (part B) is not negative, the sign is not flipped.

Step-by-step explanation:

Hope this helped!!

8 0

3 years ago

Read 2 more answers

The coordinates of the vertices for rectangle ABCD are A (2,4), B (6,10), C (9,8) and D (5,2). What

sweet [91]

Answer:

D. $\sqrt{65}$

Step-by-step explanation:

The computation of the length of a diagonal (AC or BD) of the rectangle is shown below:

As we know that

The Diagonal length of AC is

$= (x_2 - x_1)^2 + (y_2 - y_1)^2\\\\= (9 -2)^2 + (8 - 4)^2\\\\= (7)^2 + (4)^2$

$= \sqrt{49 + 16}\\\\= \sqrt{65}$

Therefore correct option is D.

3 0

3 years ago

In the morning, Jasmine biked to her grandma's house in 45 minutes. When she was biking back home in the evening it was foggy an

Mars2501 [29]

Let x = speed and y = distance

y = x * 45

y = (x - 4) * 70

45x = 70x - 280

-25x = -280

x = 11.2

Put it back into the first equation:

y = 11.2 x 45

y = 504miles

Hope this helps! Any questions let me know :)

7 0

3 years ago

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d

kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!