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Kisachek [45]
3 years ago
5

Javier worked 45 hours last week. His hourly rate for hours worked is $ 8.75 . After his 40 hour work week, he is paid time and

a half for overtime. What is Javier’s gross pay for last week?
Mathematics
2 answers:
DanielleElmas [232]3 years ago
6 0

Answer:

tondala se Banda Nawaz santsang condone antaryami kavya sundari saga

dangina [55]3 years ago
6 0
Pay for regular time = 40 hours x $8.75 = $350

Pay for overtime:
45-40= 5 hours

Overtime rate = $8.75 x 1.5 = 13.125

> 13.125 x 5 = 65.625

His gross pay= 65.625 + $350 = $415.625
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A spherical fish bowl is half-filled with water. The center of the bowl is C, and the length of segment AB is 20 inches, as show
aleksandrvk [35]
I found the picture of the bowl.

AB is the diameter of the sphere.

So the radius is 20in / 2 = 10 in

And the volume of water is half the volume of the sphere.

=> V of water = (1/2)* (4/3) π (r^3)

Also, this problems asks to use 22/7 as approximation of π.

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3 years ago
FITNESS Alejandro is a personal trainer. For his clients to gain the maximum benefit from their exercise, Alejandro calculates t
katen-ka-za [31]

Answer:

1). f^{-1}(x) = (200 - \frac{x}{0.85})

2). Inverse function represents the age of the client and 'x' represents the maximum heart rate of the client.

Step-by-step explanation:

Function representing the maximum heart rate is,

f(x) = 0.85(220 - x)

Here x = age of the client

Equation form of the function will be,

y = 0.85(220 - x)

To get the inverse of the given function, replace 'x' by 'y' and 'y' by 'x' and solve for y.

x = 0.85(220 - y)

220 - y = \frac{x}{0.85}

y = 220 - \frac{x}{0.85}

Now convert this equation into a function.

f^{-1}(x) = (200 - \frac{x}{0.85})

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8 0
4 years ago
The quality control manager at a computer manufacturing company believes that the mean life of a computer is 120 months, with a
IrinaK [193]

Answer:

P(X<118.81)=0.0803

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The sampling distribution mean will be equal to the mean for a single computer:

\mu_{89}=\mu=120

The standard deviation will be adjusted by the sample size as:

\sigma_{89}=\sqrt{\sigma^2/n}=\sqrt{64/89}=\sqrt{0.719}=0.848

With these parameters, we can calculate the z-score for X=118.81.

z=\dfrac{X-\mu}{\sigma}=\dfrac{118.81-120}{0.848}=\dfrac{-1.19}{0.848}=-1.403

Then, the probability that the mean of a sample of 89 computers is less than 118.81 months is:

P(X

7 0
4 years ago
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