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Sunny_sXe [5.5K]
3 years ago
7

What is -3/2 - 7/4 + 1/8

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

3/8

Step-by-step explanation:

-3/2 can change to -12/8

7/4 can change to 14/8

1/8 stays the same

-12/8 + 14/8 = 2/8 + 1/8 = 3/8

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Suppose the variable x is represented by a standard normal distribution. What is the probability of x > 0.3 ? Please specify
uysha [10]

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

5 0
2 years ago
- 3 (n-3)-5<br> simplify the expression using distributive property please rnnn
Tju [1.3M]
Distribute the “-3” to both n&-3 —> -3n+9 then your left with -5 and subtract 9-5

-3n+4

Hope this helps:)
4 0
3 years ago
Subtract a number plus 6 from a number minus 10
mash [69]

Answer:

(n+6)-(n-10)

Step-by-step explanation:

n is the number.

plus means addition

minus means subtraction

6 0
3 years ago
How do you find cube of the measure of one edge of a bird cage
Svetlanka [38]
Measure × measure × measure
6 0
3 years ago
There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc
sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0
3 years ago
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