Factors of -100
-1,100 or 1,-100
-2,50 or 2,-50
-4,25 or 4,-25
-5,20 or 5,-20
-10,10
now through trial and error we add these together until we get 8 which is...
none of these, are you sure that you have the correct numbers?
Answer:
2x³+3x²-8x+3
Step-by-step explanation:
So we know x=½,x=1 and x=-3
Then (2x-1)(x-1)(x+3) are the factors
(2x-1)[(x²+3x-x-3)]
(2x-1)[(x²+2x-3)]
2x³+4x²-6x-x²-2x+3
2x³+3x²-8x+3
Answer:
Step-by-step explanation:
From the question we are told that:
Sample size n=9
Number of Green 
Number of yellow 
Number of white 
Probability of Green Followed by yellow P(GY) ball
Generally the equations for when n is even is mathematically given by
Therefore
Generally the equations for when n is odd is mathematically given by
b)
Probability of drawing white ball
Therefore
Therefore
![E(y)=[E(w)-1]\frac{4}{9}](https://tex.z-dn.net/?f=E%28y%29%3D%5BE%28w%29-1%5D%5Cfrac%7B4%7D%7B9%7D)
![E(y)=[\frac{9}{2}-1]\frac{4}{9}](https://tex.z-dn.net/?f=E%28y%29%3D%5B%5Cfrac%7B9%7D%7B2%7D-1%5D%5Cfrac%7B4%7D%7B9%7D)
the answer is C. 7 because 328 divided by 50 is 6.56 so it would round to 7
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
